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MATH 1150 · Radical expressions · Objective 1.1

Domain, Range, and Intercepts of Square-Root Graphs

Read key graph features directly from radical function structure.

CLO 1 · Topic 11 of 21
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Build the concept from the beginning

Meaning before procedure

For f(x) = a√(x − h) + k, the domain begins at x = h. The range begins at k and goes upward when a > 0 or downward when a < 0. Intercepts are found by setting x or y equal to zero while respecting the domain.

Domain boundary
x = h, where the radicand first becomes zero.
Range direction
Up for a > 0; down for a < 0.
x-intercept
A point where y = 0.
y-intercept
A point where x = 0, if 0 is in the domain.

Interactive visual model

Track how the endpoint and the sign of a control domain and range.

Change one control at a time and describe what changes—and what stays invariant.

A dependable four-step method

Find h from the radicand.
Use the sign of a to determine range direction.
Set x = 0 for a possible y-intercept.
Set y = 0 for x-intercepts and reject inputs outside the domain.
  1. Find h from the radicand.
  2. Use the sign of a to determine range direction.
  3. Set x = 0 for a possible y-intercept.
  4. Set y = 0 for x-intercepts and reject inputs outside the domain.
Three fully explained examples

Watch the reasoning, not just the answer

Example 1: Find domain and range of y = 3√(x − 2) − 4.

Name the goalEndpoint is (2,−4).
Choose the next movea is positive, so the graph rises.
Carry out the mathematicsDomain x ≥ 2; range y ≥ −4.
Check and interpretThe live graph begins at (2,−4) and extends right/up.

Example 2: Find the y-intercept of y = √(x + 9) − 1.

Name the goalCheck x = 0 is allowed.
Choose the next moveSubstitute x = 0.
Carry out the mathematicsy = √9 − 1 = 2, so (0,2).
Check and interpretThe point satisfies the original function.

Example 3: Find the x-intercept of y = √(x − 1) − 3.

Name the goalSet y = 0.
Choose the next moveSolve √(x − 1) = 3.
Carry out the mathematicsx − 1 = 9, so x = 10 and the intercept is (10,0).
Check and interpret10 is in the domain x ≥ 1 and substitution gives 0.
Interactive practice

Predict, decide, check, and revise

Interactive construction lab

Build a valid reasoning path

Choose the decisions in the order a careful solver would use them for this concept.

Choose this step, then check the construction.
Choose this step, then check the construction.
Choose this step, then check the construction.

The reasoning path changes as each decision is selected.

Readiness check

Check the foundation

State domain and range of y = 1√(x − (2)) + (-4).

State domain and range of y = 3√(x − (-1)) + (2).

Not completed yet.
Guided practice

Apply the method with support

State domain and range of y = -1√(x − (4)) + (5).

State domain and range of y = -2√(x − (-3)) + (1).

State domain and range of y = 2√(x − (0)) + (-2).

Not completed yet.
Independent practice

Work without step prompts

State domain and range of y = 1√(x − (5)) + (3).

State domain and range of y = -3√(x − (2)) + (-1).

State domain and range of y = 4√(x − (-4)) + (0).

State domain and range of y = 1√(x − (1)) + (1).

Not completed yet.
Mastery check

Demonstrate durable understanding

State domain and range of y = -1√(x − (-2)) + (-5).

State domain and range of y = 2√(x − (6)) + (-3).

State domain and range of y = -2√(x − (3)) + (4).

State domain and range of y = 5√(x − (-5)) + (2).

State domain and range of y = -4√(x − (0)) + (6).

Not completed yet.
Unfamiliar transfer

Explain, compare, and revise

Analyze y = −2√(x + 4) + 6: endpoint, domain, range, and both intercepts.

Write a first attempt before opening the self-check.

The learner record reveals exact answers and model reasoning only after an attempt.